30 September 2010

Engineering Graphics ''Parabola''

Parabola





Parabola Rectangle Method


PROBLEM 1 : A BALL THROWN IN AIR ATTAINS 100 M HIEGHT AND COVERS HORIZONTAL DISTANCE 150 M ON GROUND. Draw the path of the ball (projectile)

Construction

Step 1. Draw rectangle of above size and divide it in two equal vertical parts

Step 2. Consider left part for construction. Divide height and length in equal number of parts and name those 1,2,3,4,5& 6

Step 3. Join vertical 1,2,3,4,5 & 6 to the top center of rectangle

Step 4. Similarly draw upward vertical lines from horizontal1,2,3,4,5 And wherever these lines intersect previously drawn inclined lines in sequence Mark those points and further join in smooth possible curve.

Step 5. Repeat the construction on right side rectangle also.Join all in sequence. This locus is Parabola .








Parabola Method of Tangent


Problem 2 : Draw an isosceles triangle of 100 mm long base and 110 mm long altitude. Inscribe a parabola in it by method of tangents.

Construction

Step 1. Construct triangle as per the given dimensions.

Step 2. Divide it’s both sides in to same no.of equal parts.

Step 3. Name the parts in ascending and descending manner, as shown.

Step 4. Join 1-1, 2-2,3-3 and so on.

Step 5. Draw the curve as shown i.e. tangent to all these lines. The above all lines being tangents to the curve, it is called method of tangents


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